7x^2+3x=92

Solution for 7x^2+3x=92 equation:

7x^2+3x=92

We move all terms to the left:

7x^2+3x-(92)=0

a = 7; b = 3; c = -92;
Δ = b2-4ac
Δ = 32-4·7·(-92)
Δ = 2585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{2585}}{2*7}=\frac{-3-\sqrt{2585}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{2585}}{2*7}=\frac{-3+\sqrt{2585}}{14}
$